1个回答
test
2024-07-14

let data = {
    listA: ['A1','A2','A3','A4','A5','A6','A7','A8','A9'],
    listB: ['B1',"B2","B3",'B4',"B5","B6","B7","B8","B9"],
    listC: ['C1',"C2","C3",'C4',"C5","C6","C7","C8","C9"]
}
let result = Object.keys(data).reduce((p,key)=>{
    for(let i = 0;i<data[key].length;i++){
        p[i] ? p[i].data.push(data[key][i]) : p[i] = {data:[data[key][i]]}
    }
    return p;
},[])回复
适合作为回答的
- 经过验证的有效解决办法
 - 自己的经验指引,对解决问题有帮助
 - 遵循 Markdown 语法排版,代码语义正确
 
不该作为回答的
- 询问内容细节或回复楼层
 - 与题目无关的内容
 - “赞”“顶”“同问”“看手册”“解决了没”等毫无意义的内容
 
转换成
,结果