如何使用python对markdown文档图片地址批量处理？

import re

def process_markdown_content(content):
   
    img_pattern = re.compile(r'!\[([^\]]*)\]\((\./[^)]+)\)')
    
    # 对每个链接进行处理
    def replacer(match):
        description = match.group(1)
        old_path = match.group(2)
        # 改图片链接为新的文件夹
        new_path = old_path.replace('./', './new_folder/')
        return f'![{description}]({new_path})'
    
    # 替换原链接为新链接
    new_content = img_pattern.sub(replacer, content)
    return new_content

# 示例
markdown_content = '''
Here is some markdown content.
![desc1](./images/pic1.jpg)
![desc2](./path/to/pic2.png)
'''

new_content = process_markdown_content(markdown_content)
new_content