通过子节点找到父节点完整路径

 const getTreeIds = (tree: any[], nodeId: any, config: {}) => {
//tree目标树，nodeId节点id
    const { children = 'cityList', id = 'adCode' } = config || {}
    const toFlatArray = (tree: any[], parentId: never[]) => {
      return tree.reduce((t: any, _: Record<string, any>) => {
        const child = _[children]
        return [
          ...t,
          parentId ? { ..._, parentId } : _,
          ...(child && child.length ? toFlatArray(child, _[id]) : [])]
      }, [])
    }

    const getIds = (flatArray: any[]) => {
      let ids = [nodeId]
      let child = flatArray.find((_: Record<string, any>) => _[id] === nodeId)
      while (child && child.parentId) {
        ids = [child.parentId, ...ids]
        // eslint-disable-next-line @typescript-eslint/no-loop-func
        child = flatArray.find((_: Record<string, any>) => _[id] === child.parentId)
      }

      return ids
    }

    return getIds(toFlatArray(tree, []))
  }